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31. $\overline{ab} + \overline{ca} + \overline{bc} = 88$ və $a \neq b \neq c$ olarsa, $\overline{abc}$ ədədinin ala biləcəyi ən böyük qiyməti ilə ən kiçik qiymətinin cəmini tapın.

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Step 1

Hi Hafiz, let's solve this math puzzle together.

Breaking Down the Equation

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Step 2

First, we represent the two-digit numbers using place values. The bar over the letters indicates they are digits of a number. So, a b equals ten a plus b, c a equals ten c plus a, and b c equals ten b plus c.

$$(10a + b) + (10c + a) + (10b + c) = 88$$
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Step 3

Now, let's group the like terms. We have eleven a plus eleven b plus eleven c equals eighty-eight.

$$11a + 11b + 11c = 88$$
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Step 4

If we divide the entire equation by eleven, we get a very simple relationship: a plus b plus c equals eight.

$$a + b + c = 8$$
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Step 5

We are given that a, b, and c are distinct digits. Remember, for the number a b c to be a three-digit number, the first digit a cannot be zero.

Finding Possible Values

$$a \neq b \neq c, \quad a \neq 0, \quad a+b+c=8$$

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About This Question

Subject
Mathematics
Topic
Number Theory
Difficulty
Medium
Question Type
Open Ended

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