Triangle Folding Geometry Problem

MathematicsGeometryHard

Published:

A piece of paper in the shape of triangle ABC is folded along segment [AD], and after folding [AC] // [DB']. $|AE| = 2 \cdot |EB'|$ and $|BD| = 3$ cm, what is $|EC|$, in cm?

This question includes visual content: The image shows two parts of a geometry problem. The top part shows a triangle ABC with a dashed line segment AD. An arrow indicates folding the triangular flap ABD along line AD. The bottom part shows the resulting shape after the fold where point B moves to B'. A new triangle AB'D is formed, and the overlap with the original base BC occurs at point E. The segment BC now contains points B, D, E, C in order. There is a blue-filled triangle A E D and a yellow-filled triangle A E C. A label '3' is placed under the segment BD. The text states |AE| = 2|EB'| and [AC] // [DB'].

Animated Video Solution

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Step by Step Written Solution

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Step 1

Hi Bekirhan, let's solve this geometry problem together. We are looking at a folding problem involving a triangle A B C.

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Step 2

We are given that triangle A B C is folded along the line A D. When we fold the triangle, the point B moves to a new position, denoted as B prime.

Folding Properties

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Step 3

Because A D is the line of reflection, certain side lengths and angles remain equal. For instance, the length B D must be equal to the length D B prime because B prime is just the image of B.

$$BD = DB' = 3\text{ cm}$$
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Step 4

Next, let's look at the parallel line condition. The problem states that segment A C is parallel to D B prime.

$$AC \parallel DB'$$
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Step 5

Let's identify some similar triangles created by these parallel lines.

Similarity and Parallel Lines

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Step 6

Notice that the line A B prime crosses the parallel lines A C and D B prime at points A, E, and B prime.

AB'E
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Step 7

Because A C is parallel to D B prime, triangle E A C is similar to triangle E B prime D by the Angle Angle similarity theorem.

$$\triangle EAC \sim \triangle EB'D$$
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Step 8

From this similarity, we can set up a ratio of corresponding sides. The ratio of E C to E D is equal to the ratio of A E to E B prime.

$$\frac{EC}{ED} = \frac{AE}{EB'}$$
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Step 9

We are given a specific ratio in the problem: A E equals two times E B prime.

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Step 10

This simplifies to tell us that the length E C is twice the length E D.

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Step 11

Now we need to connect this to the length B D, which we know is 3 centimeters.

Using the Angle Bisector

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Step 12

Remember that because A D is a line of reflection for the fold, the angle B A D must equal the angle D A B prime.

$$\angle BAD = \angle DAB'$$

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About This Question

Subject
Mathematics
Topic
Geometry
Difficulty
Hard
Question Type
Multiple Choice

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