Finding Local Extrema Using the Second-Derivative Test

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EXAMPLE 2 Testing Local Extrema Find the local maxima and minima for each function. Use the second-derivative test for local extrema when it applies. (A) $f(x) = x^3 - 6x^2 + 9x + 1$

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Step 1

Hi Ayliz, let's find the local maxima and minima for this cubic function using the second derivative test.

Finding Local Extrema

$$f(x) = x^3 - 6x^2 + 9x + 1$$
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Step 2

To find local extrema, our first step is to calculate the first derivative and find the critical points.

Step 1: Find Critical Points

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Step 3

Using the power rule, the derivative f prime of x is three x squared minus twelve x plus nine.

$$f'(x) = 3x^2 - 12x + 9$$
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Step 4

We set this derivative equal to zero to solve for our critical values.

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Step 5

To make solving easier, let's factor out a three from the entire equation.

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Step 6

Now we factor the quadratic inside the parentheses. We need two numbers that multiply to three and add to negative four.

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Step 7

Setting each factor to zero, we find our critical points at x equals one and x equals three.

$$x = 1, \quad x = 3$$

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About This Question

Subject
Mathematics
Topic
Calculus
Difficulty
Medium
Question Type
Open Ended

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