Complete Table and Graphing Quadratic Equations
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7 (a) Copy and complete the table of values for the relation $y = 2x^2 - x - 2$ for $-4 \le x \le 4$.
| x | -4 | -3 | -2 | -1 | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|---|---|---|---|
| y | | 19 | | | -2 | | | | 26 |
(b) Using a scale of $2\text{ cm}$ to $1\text{ unit}$ on the $x$-axis and $2\text{ cm}$ to $5\text{ units}$ on the $y$-axis, draw the graph of $y = 2x^2 - x - 2$ for $-4 \le x \le 4$.
(c) On the same axes, draw the graph of $y = 2x + 3$.
(d) Use the graph to find the: (i) roots of the equation $2x - 3x - 5 = 0$; (i) range of values of $x$ for which $2x^2 - x - 2 < 0$.
This question includes visual content: A table with two rows: the first row contains x-values from -4 to 4, and the second row contains y-values corresponding to the quadratic function $y = 2x^2 - x - 2$. Some cells in the table are empty, while others are filled: for $x = -4$, $y = 19$; for $x = -3$, $y = 19$; for $x = 0$, $y = -2$; for $x = 4$, $y = 26$.
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Hi Martin, let's solve this quadratic graphing problem together. We'll start by completing the table of values.
Part (a): Table of Values
Function: $y = 2x^2 - x - 2$
We need to find the missing y values for x equals negative four, negative two, negative one, one, two, and three.
| x | -4 | -3 | -2 | -1 | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|---|---|---|---|
| y | 19 | -2 | 26 |
When x is negative four, y equals two times negative four squared, minus negative four, minus two. This gives us thirty-two plus four minus two, which is thirty-four.
Next, for x equals negative two, we have two times four, plus two, minus two, which equals eight.
For x equals negative one, we calculate two times one, plus one, minus two, which is one.
Now for the positive side. When x is one, y equals two, minus one, minus two, which is negative one.
When x is two, we get two times four, minus two, minus two, resulting in four.
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