Bacterial Growth Calculation
Yayınlanma:
7. Aşağıdaki deney tüplerinden 1. sinde $4 \cdot 6^6$ adet 2. sinde $8^5$ adet bakteri bulunmaktadır. 1. tüpteki bakteriler her 1 saat sonunda 2 katına, 2. tüpteki bakteriler her 1 saat sonunda 3 katına çıkmaktadır.
Buna göre 6 saatin sonunda tüplerdeki toplam bakteri sayısı aşağıdakilerden hangisidir?
A) $12^6$
B) $12^7$
C) $12^8$
D) $12^9$
E) $12^{10}$
Soruda görsel içerik var: The image shows two test tubes placed vertically, one above the other. The top test tube contains a red liquid, and the bottom one contains a green liquid. Handwritten markings are visible next to the test tubes, showing expressions like '4.6^6' and '8^5'.
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Adım Adım Yazılı Çözüm
In this problem, we are given two test tubes containing bacteria that multiply every hour, and we need to find the total number of bacteria after six hours.
Bacteria Growth Problem
Let's first list the given information for both test tubes.
• Tube 1: starts with $4 \cdot 6^6$ bacteria and doubles every hour.
• Tube 2: starts with $8^5$ bacteria and triples every hour.
Let's calculate the number of bacteria in the first test tube after six hours.
Bacteria in Test Tube 1
Since both six and two are raised to the power of six, we can combine them using exponent rules.
Recall that $a^n \cdot b^n = (a \cdot b)^n$.
This gives us four times the quantity six times two to the sixth power.
Six times two is twelve, so the first tube contains four times twelve to the sixth bacteria.
Now, let's calculate the bacteria in the second test tube after six hours.
Bacteria in Test Tube 2
First, we express eight as a power of two, which is two cubed.
Multiplying the exponents gives two to the power of fifteen.
To match the power of six, we can split two to the fifteenth into two cubed times two to the twelfth.
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