Slopes and Angles of a Line in an Orthonormal System

MathematicsAnalytic GeometryEasySTEM

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**Exercise 8:**

In an orthonormal system $(x'Ox \ ; \ y'Oy)$ consider the points $A(0 \ ; \ 2)$ and $B(3 \ ; \ -1)$.

1) Find the slope of straight line $(AB)$.

2) Find the value of the acute angle $\alpha$ formed by $(AB)$ and $x'Ox$.

3) Deduce the value of the acute angle $\beta$ formed by $(AB)$ and $y'Oy$.

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Step by Step Written Solution

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Step 1

In this problem, we are working with an orthonormal system and two points, A at zero two, and B at three negative one. We need to find the slope of line A B, and the angles it forms with the coordinate axes.

Coordinate Geometry Problem

$$A(0, 2), \quad B(3, -1)$$
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Step 2

For the first part, let's calculate the slope m of the straight line A B using the slope formula.


1) Slope of (AB)

$$m = \frac{y_B - y_A}{x_B - x_A}$$
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Step 3

Plugging in our coordinates, we have negative one minus two over three minus zero.

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Step 4

This simplifies to negative three over three, which results in a slope of negative one.

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Step 5

Now for part two, we need the acute angle alpha formed by the line A B and the x-axis. We know the relationship between slope and the angle is that the slope equals the tangent of the angle of inclination.

2) Angle $\alpha$ with x'Ox

$$\tan(\theta) = m = -1$$
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Step 6

Since the slope is negative one, the angle of inclination theta is one hundred and thirty-five degrees. However, the question asks for the acute angle alpha.

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About This Question

Subject
Mathematics
Topic
Analytic Geometry
Difficulty
Easy
Exam
STEM
Question Type
Open Ended

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