Properties of Triangle Medians in Coordinate Geometry

MathematicsAnalytic GeometryHard

Published:

A median of a triangle is a line segment from a vertex to the midpoint of the opposite side.

a Show that the median OP has equation $cx - (a + b)y = 0$.

b Show that the median AQ has equation $cx - (b - 2a)y = 2ac$.

c Prove that the third median BR passes through the point of intersection G of medians OP and AQ.

This question includes visual content: The image shows a triangle OBA on a Cartesian plane with vertices at O(0,0), A(2a,0), and B(2b,2c). Three medians are drawn: OP (to side AB), AQ (to side OB), and BR (to side OA). The intersection of the medians is labeled G. The sides are marked with hash marks indicating equal segments (midpoints P, Q, R). A faint vertical dashed line drops from P to the x-axis.

Animated Video Solution

The first half plays free, the full solution is in the app.

Step by Step Written Solution

1
Step 1

Hi Melek, let's look at this coordinate geometry problem exploring the properties of medians in a triangle.

Triangle Median Proof

2
Step 2

First, let's identify our vertices from the diagram. Vertex O is at the origin, A is at two a, zero, and B is at two b, two c.

Vertices

- $O(0, 0)$

- $A(2a, 0)$

- $B(2b, 2c)$

3
Step 3

For part a, we need the equation for median O P. P is the midpoint of side A B.

Part (a): Median OP

$$P = \left( \frac{x_A + x_B}{2}, \frac{y_A + y_B}{2} \right)$$
4
Step 4

Substituting the coordinates of A and B, we find that P is at a plus b, c.

5
Step 5

Since median O P passes through the origin 0, 0 and P, its gradient m is c over a plus b.

$$m_{OP} = \frac{c - 0}{(a + b) - 0} = \frac{c}{a+b}$$
6
Step 6

Using the line equation y equals m x, we get y equals c over a plus b times x.

$$y = \frac{c}{a+b}x$$
7
Step 7

Cross multiplying and rearranging, we get c x minus, bracket, a plus b, bracket, y equals zero. This proves part a.

8
Step 8

Now for part b, we find median A Q. Q is the midpoint of side O B.

Part (b): Median AQ

$$Q = \left( \frac{0 + 2b}{2}, \frac{0 + 2c}{2} \right) = (b, c)$$
9
Step 9

The gradient of A Q, from A at two a, zero to Q at b, c, is c minus zero over b minus two a.

$$m_{AQ} = \frac{c - 0}{b - 2a} = \frac{c}{b - 2a}$$
10
Step 10

Using the point-slope form with point A, we have y minus zero equals the gradient times x minus two a.

$$y - 0 = \frac{c}{b - 2a}(x - 2a)$$
11
Step 11

Multiply both sides by b minus two a to clear the fraction.

12
Step 12

Expanding the right side gives c x minus two a c. Moving the terms, we get c x minus, bracket, b minus two a, bracket, y equals two a c. That's our second equation.

The rest of this solution is on Solvi

12 more steps are locked. Watch the full animated, narrated solution for free.

Snap a photo, solve any question like this.

Download on the App Store Get it on Google Play

Free to download · First solutions are on us

100K+Questions solved daily
50K+Students learning
4.8 ★App Store rating

About This Question

Subject
Mathematics
Topic
Analytic Geometry
Difficulty
Hard
Question Type
Proof

Solve any question in seconds

Snap a photo and AI explains it step by step with voice and animation.

Download on the App Store Get it on Google Play
Solvi
The full solution is in the appFree to download · First solutions are on us
Get