Modular Arithmetic Exercises

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Find the least positive value of $x$ such that

(i) $71 \equiv x \pmod{8}$

(ii) $78 + x \equiv 3 \pmod{5}$

(iv) $96 \equiv \frac{x}{7} \pmod{5}$

(v) $5x \equiv 4 \pmod{6}$

If $x$ is congruent to 13 modulo 17 then $7x - 3$ is congruent to...

Solve $5x \equiv 4 \pmod{6}$

Solve $3x - 2 \equiv 0 \pmod{11}$

What is the time 100 hours after 7 a.m.?

What is the time 15 hours before 11 p.m.?

Today is Tuesday. My uncle will come after 45 days. In which day is my uncle coming?

Prove that $2^n + 6 \times 9^n$ is always divisible by 7 for any positive integer $n$.

Find the remainder when $2^{81}$ is divided by 17.

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Step by Step Written Solution

1
Step 1

Hi Pushpa, let's solve this interesting modular arithmetic problem together. We're looking for the remainder when two to the power of eighty-one is divided by seventeen.

Problem Summary

Find the remainder: $2^{81} \pmod{17}$

2
Step 2

To solve this efficiently, we'll use properties of congruences and power cycles. Let's start by finding a power of two that is close to a multiple of seventeen.

Step 1: Find a base power

$$2^1 \equiv 2 \pmod{17}$$
$$2^2 \equiv 4 \pmod{17}$$
$$2^3 \equiv 8 \pmod{17}$$
$$2^4 \equiv 16 \pmod{17}$$
3
Step 3

Notice that sixteen is extremely useful because it is congruent to negative one modulo seventeen. This will simplify our calculations significantly.

4
Step 4

So we can write sixteen as negative one modulo seventeen.

$$2^4 \equiv -1 \pmod{17}$$
5
Step 5

Now, we need to express our original exponent, eighty-one, in terms of our base exponent, four. Using the division algorithm, we know that eighty-one equals four times twenty plus one.

Step 2: Rewrite the exponent

$$81 = 4(20) + 1$$

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About This Question

Subject
Mathematics
Topic
Modular Arithmetic
Difficulty
Medium
Exam
STEM
Question Type
Open Ended

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