Üçgende Benzerlik Sorusu

9. ABC ve AED birer üçgen, $m(\widehat{AED}) = m(\widehat{ABC})$

$|AC| = |AD| = 4 \text{ cm}$, $|EC| = 6 \text{ cm}$

$|BD| = (x + 2) \text{ cm}$ olduğuna göre, $x$ kaç cm'dir?

A) 2

B) 3

C) 4

D) 5

E)

Soruda görsel içerik var: A geometric figure shows two intersecting triangles, ABC and AED, sharing a common vertex A. Points C and E lie on one ray from A, and points D and B lie on another ray from A. Segment BC and segment ED intersect at point F. The segments are labeled with lengths: |AC| = 4, |CE| = 6 (making |AE| = 10), |AD| = 4, and |DB| = x + 2 (making |AB| = 4 + x + 2 = x + 6). In triangle AED, the angle at vertex E is marked with a single arc and a tick mark. In triangle ABC, the angle at vertex B is marked with the same symbol, indicating they are equal: m(AED) = m(ABC). The common angle at vertex A is shared by both triangles.