Test Pass Percentage Calculation from Frequency Table
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Logical reasoning and problem-solving
5. The following table shows the results of a test:
| mark | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| :--- | :--- | :--- | :--- | :--- | :--- | :--- | :--- | :--- | :--- | :--- | :--- |
| frequency | 1 | 4 | 4 | 6 | 2 | 1 | 1 | 2 | 2 | 1 | 0 |
To pass the test, a mark of higher than 5 is needed. What percentage of the candidates passed the test?
A) $25\%$
B) $24\%$
C) $20\%$
D) $30\%$
E) $50\%$
This question includes visual content: A horizontal table with two rows. The first row is labeled 'mark' and contains values from 0 to 10. The second row is labeled 'frequency' and contains the corresponding number of candidates for each mark. The values are: Mark 0: Freq 1; Mark 1: Freq 4; Mark 2: Freq 4; Mark 3: Freq 6; Mark 4: Freq 2; Mark 5: Freq 1; Mark 6: Freq 1; Mark 7: Freq 2; Mark 8: Freq 2; Mark 9: Freq 1; Mark 10: Freq 0.
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Step by Step Written Solution
Hello! Today we are looking at a test result table and finding out what percentage of candidates passed the test. To pass, a candidate needs a mark higher than five.
Test Pass Percentage Analysis
First, let's calculate the total number of candidates who took the test by adding up all the frequencies in the second row.
Adding these numbers together, one plus four plus four plus six plus two plus one plus one plus two plus two plus one gives us a total of twenty-four candidates.
Now, let's identify how many candidates passed. The problem states a mark higher than five is needed. This means we only count candidates with marks of six, seven, eight, nine, or ten.
Candidates who Passed (Mark > 5)
Looking at the table, one student got a mark of six, two students got a seven, two students got an eight, one student got a nine, and zero students got a ten.
Adding those up, we find that exactly six candidates passed the test.
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