Simplifying Rational Expressions and Partial Fraction Decomposition

MathematicsRational Expressions and Partial FractionsMediumSTEM

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3. Find the domain and perform each of the following indicated operations for:

a. $\frac{x-1}{x+2} + \frac{x+3}{x^2+6x+5}$

b. $\frac{x-1}{x+2} - \frac{x+3}{x^2+6x+5}$

c. $\frac{(x-1)}{(x+2)} \times \frac{(x+3)}{(x^2+6x+5)}$

d. $\frac{x-1}{x+2} \div \frac{x+3}{x^2+6x+5}$

4. Write each of the following rational expressions as sum of partial fractions:

a. $\frac{5x+6}{x^2-4}$

b. $\frac{x+6}{x^2-4x+4}$

c. $\frac{6x+5}{x^4+4x^2}$

d. $\frac{x^2+x+2}{x^2+6x+8}$

e. $\frac{x^3+2x^2+2}{x^2-x-6}$

5. Solve each of the following rational equations.

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1
Step 1

Today we are going to perform the operation indicated for this rational expression and find its domain. We have two rational expressions multiplied together.

Multiplying Rational Expressions

$$\frac{x-1}{x+2} \times \frac{x+3}{x^2+6x+5}$$
2
Step 2

To simplify this, we should first factor all the polynomials in the numerators and denominators.

Step 1: Factor everything

3
Step 3

The numerator x minus one, the denominator x plus two, and the second numerator x plus three are already in their simplest linear form. Let's focus on the quadratic expression x squared plus six x plus five.

4
Step 4

We need two numbers that multiply to five and add up to six. Those numbers are five and one.

$$x^2 + 6x + 5 = (x+5)(x+1)$$
5
Step 5

Now, let's rewrite the original expression using the factored form of the denominator.

6
Step 6

Before we multiply, we must determine the domain. The domain consists of all real values of x except those that make any denominator zero.

Finding the Domain

$$(x+2) = 0, \quad (x+5) = 0, \quad (x+1) = 0$$

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About This Question

Subject
Mathematics
Topic
Rational Expressions and Partial Fractions
Difficulty
Medium
Exam
STEM
Question Type
Open Ended

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