Group Theory: Modular Arithmetic and Linear Functions

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The set $S = \{a; 2; 4; 6\}$ forms a group under the operation addition modulo 8.

(i) Write down the value of $a$.

(ii) Construct a Cayley table for $S; +_8$.

Show that the set of functions of the form $f(x) = px + q$, where $p; q \in \mathbb{R}$ and $p \neq 0$, forms a group under composition of functions.

Animated Video Solution

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Step by Step Written Solution

1
Step 1

In this problem, we'll explore group theory. First, we'll work with a finite set of integers under modular addition, and then we'll prove that a specific set of linear functions forms a group under composition.

Group Theory Analysis

2
Step 2

Part one gives us a set S containing an unknown element 'a', along with 2, 4, and 6. This set forms a group under addition modulo 8. For any group, the identity element must be present in the set.

$$S = \{a, 2, 4, 6\}$$
3
Step 3

In the group of integers under addition modulo 8, the identity element is zero. Therefore, 'a' must be equal to 0 for the set to satisfy the identity axiom of group theory.

4
Step 4

Now, let's construct the Cayley table for this set under addition modulo 8. We perform addition and take the remainder when divided by 8.

(ii) Cayley Table for $(S, +_8)$

5
Step 5

We arrange our elements 0, 2, 4, and 6 in rows and columns. Adding 0 to any element keeps it the same. Adding 2 plus 2 gives 4, 2 plus 4 gives 6, and 2 plus 6 is 8, which is 0 in modulo 8.

+_80246
--------------
00246
22460
44602
66024
6
Step 6

Observe that every row and column contains each element exactly once, and all results are within the set, confirming it is indeed a group.

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Step 7

Now let's move to the second part. We want to show that functions of the form f of x equals p x plus q form a group under composition. To prove this, we must check four axioms: closure, associativity, identity, and inverse.

Proof: Set of Linear Functions

$F = \{f(x) = px + q \mid p, q \in \mathbb{R}, p \neq 0\}$

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Step 8

First, closure. Let's take two functions, f and g. Their composition involves plugging g into f.

$$ (f \circ g)(x) = p_1(p_2x + q_2) + q_1$$

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About This Question

Subject
Mathematics
Topic
Group Theory
Difficulty
Medium
Exam
STEM
Question Type
Open Ended

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