Doğruda Açılar ve Açıortay Problemi

10.

BA // ED // FG

$[BD]$ açıortay

$[FE]$ açıortay

$m(\widehat{FED}) = 150^\circ$

$m(\widehat{BDE}) = 40^\circ$

Buna göre $m(\widehat{BCF})$ kaç derecedir?

A) 130

B) 140

C) 145

D) 150

E) 155

Soruda görsel içerik var: The image shows a geometric figure with three parallel horizontal lines: BA at the top, ED in the middle, and FG at the bottom. Point B is on the top line, pointing left. Point F is on the bottom line, pointing left. Point D is at the end of the middle line segment ED. There is a zigzag shape connecting B to C to F. A line segment BD acts as an angle bisector for angle ABC, and FE acts as an angle bisector for angle CFG. The angle m(FED) is labeled as $150^\circ$ and m(BDE) is labeled as $40^\circ$. The angle to be found is m(BCF). Points are labeled B, A, C, E, D, F, G. Symbols indicate that BD and FE are angle bisectors.