Verifying the Height of an Equilateral Triangle
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3. Model with Math $\triangle LMN$ is an equilateral triangle. Is $\overline{MQ}$ the height of $\triangle LMN$? Explain.
[Diagram: A triangle LMN where side $LM = \sqrt{30}$, segment $LQ = \frac{\sqrt{30}}{2}$, and segment $MQ = \sqrt{15}$. $Q$ is a point on $LN$.]
This question includes visual content: A diagram shows a triangle LMN. Line segment MQ is drawn from vertex M to side LN. The side LM is labeled with the length $\sqrt{30}$. The segment LQ, which is part of the base LN, is labeled with the length $\frac{\sqrt{30}}{2}$. The segment MQ is labeled with the length $\sqrt{15}$. The triangle LMN is described in the text as an equilateral triangle.
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In this problem, we're asked to determine if the line segment M Q is the height of the equilateral triangle L M N, given the side lengths shown in the diagram.
Is $MQ$ the height of $\triangle LMN$?
If M Q is indeed the height of an equilateral triangle, it must be perpendicular to the base. This means triangle L M Q would have to be a right-angled triangle.
For $MQ$ to be the height, $\triangle LMQ$ must be a right triangle.
We can verify this by checking if the lengths satisfy the Pythagorean theorem: a squared plus b squared equals c squared.
Let's list our known values from the diagram. The side L M is the square root of thirty.
Given Values
Now, let's substitute these into the left side of our Pythagorean equation. We'll find the sum of the squares of L Q and M Q.
Squaring the first term, the square root of thirty squared is thirty, and two squared is four. So we get thirty over four.
Simplifying thirty over four gives us seven point five. Then, the square of the square root of fifteen is simply fifteen.
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