Solving a Radical Equation
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8. $3\sqrt[4]{2x-4} + 2 = 8$
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Let's solve this radical equation for x. The problem is three times the cube root of two x minus four, plus two equals eight.
Solving a Radical Equation
Our first goal is to isolate the cube root term. Let's start by subtracting two from both sides of the equation.
When we subtract two from eight, we are left with six on the right side.
So, three times the cube root of two x minus four equals six.
Next, we divide both sides by three to further isolate the cube root.
Six divided by three is simply two. Now we have the cube root of two x minus four equals two.
To eliminate the cube root, we need to cube both sides of the equation.
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