Delivery Robot Motion Analysis

PhysicsKinematicsEasySTEM

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9. A delivery robot moves $1.2 \text{ km}$ east, then $300 \text{ m}$ west. The whole trip takes $6$ minutes. a) Convert $1.2 \text{ km}$ into metres. b) Calculate the total distance travelled. c) Calculate the displacement. d) Convert the total time into seconds. e) Calculate the average speed. f) Calculate the average velocity.

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Step by Step Written Solution

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Step 1

Hi Sinan, let's solve this physics problem about a delivery robot's motion step by step.

Given Information

- Motion 1: $1.2 \; \text{km}$ East

- Motion 2: $300 \; \text{m}$ West

- Total Time: $6 \; \text{min}$

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Step 2

First, for part a, we need to convert one point two kilometers into meters.

a) Convert $1.2 \; \text{km}$ to metres

$$1 \; \text{km} = 1000 \; \text{m}$$
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Step 3

Multiplying one point two by one thousand, we get twelve hundred meters.

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Step 4

Now for part b, we calculate the total distance travelled. Distance is a scalar quantity, so we simply add the lengths of both paths.

b) Total Distance

$$d = d_1 + d_2$$
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Step 5

That is twelve hundred meters plus three hundred meters, which equals fifteen hundred meters.

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Step 6

In part c, we find the displacement. Displacement is a vector, meaning direction matters. Let's look at a diagram.

c) Calculate Displacement

1200 m (East)300 m (West)
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Step 7

Since West is opposite to East, we subtract the magnitudes. Twelve hundred minus three hundred gives us a displacement of nine hundred meters to the East.

$$\vec{\Delta x} = 1200 \; \text{m [E]} - 300 \; \text{m [W]} = 900 \; \text{m [E]}$$

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About This Question

Subject
Physics
Topic
Kinematics
Difficulty
Easy
Exam
STEM
Question Type
Open Ended

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