Finding the foot of the perpendicular from a point to a line in 3D

Mathematics3D GeometryMediumJEE

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If $A(1, 2, 3)$, $B(4, 5, 6)$ are two points then find the foot of perpendicular from $B$ to the line joining origin and $A$.

This question includes visual content: A simple sketch showing a line segment OA passing through the origin O(0, 0, 0) and point A(1, 2, 3). A line segment BM is drawn from point B(4, 5, 6) to a point M on OA such that BM is perpendicular to OA. M is labeled with coordinates (x, y, z).

Animated Video Solution

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Step by Step Written Solution

1
Step 1

Hi Tanishka, let's solve this three-dimensional geometry problem together. We are given the origin point O, point A, and point B. We need to find the foot of the perpendicular from B to the line OA.

Foot of a Perpendicular

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Step 2

Let's visualize this scenario. Here is the line passing through the origin O and the point A. We let M with coordinates x, y, z be the foot of the perpendicular drawn from point B to the line OA.

O(0,0,0)A(1,2,3)M(x, y, z)B(4,5,6)
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Step 3

Let's start by finding the equation of the line OA. First, the direction ratios of the line OA are simply the differences of the coordinates of A and the origin O.

Line OA and Parametric Form

$$\text{Direction ratios of line } OA = (1 - 0, 2 - 0, 3 - 0) = (1, 2, 3)$$
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Step 4

Since the line passes through the origin and has these direction ratios, we can write its symmetric equation as x over one equals y over two equals z over three.

$$\frac{x}{1} = \frac{y}{2} = \frac{z}{3}$$
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Step 5

Let's set this equal to a scalar constant, k. This allows us to write any general point M on the line in terms of k.

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Step 6

By equating each term to k, we find that the coordinates of M are k, two k, and three k.

$$M = (k, 2k, 3k)$$
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Step 7

Now, let's find the direction ratios of the line segment BM. We subtract the coordinates of B from the coordinates of M.

Perpendicularity Condition

$$\text{Direction ratios of } BM = (k - 4, 2k - 5, 3k - 6)$$
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Step 8

Since BM is perpendicular to OA, the dot product of their direction ratios must equal zero.

$$\vec{BM} \cdot \vec{OA} = 0$$

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About This Question

Subject
Mathematics
Topic
3D Geometry
Difficulty
Medium
Exam
JEE
Question Type
Open Ended

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