Verifying a Harmonic Function via Laplace Equation

MathematicsMultivariable CalculusMediumSTEM

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d) Harmonic functions satisfy the Laplace equations $\frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0$. Hence, show that $u(x, y) = x^2 - y^2 - y$ is harmonic (3 marks)

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Step by Step Written Solution

1
Step 1

In this problem, we are asked to show that a given multivariable function is harmonic. A function is harmonic if it satisfies Laplace's equation.

Harmonic Functions

2
Step 2

First, let's write down the definition provided. Laplace's equation states that the sum of the second partial derivatives with respect to x and y must be zero.

$$\frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0$$
3
Step 3

The function we need to test is u of x comma y equals x squared minus y squared minus y.

$$u(x, y) = x^2 - y^2 - y$$
4
Step 4

To check if the equation holds, we first need to compute the partial derivatives with respect to x. Let's start with the first partial derivative.

Differentiating with respect to x

$$u = x^2 - y^2 - y$$
5
Step 5

Differentiating with respect to x, we treat y as a constant. The derivative of x squared is two x, and the other terms drop to zero.

$$\frac{\partial u}{\partial x} = 2x$$
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Step 6

Now, we find the second partial derivative with respect to x by differentiating two x. This gives us two.

$$\frac{\partial^2 u}{\partial x^2} = 2$$
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Step 7

Now, let's perform the same steps with respect to y. We rewrite our function first.

Differentiating with respect to y

$$u = x^2 - y^2 - y$$

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About This Question

Subject
Mathematics
Topic
Multivariable Calculus
Difficulty
Medium
Exam
STEM
Question Type
Proof

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