Tension and Spring Force in an Accelerating System

PhysicsNewton's Laws of MotionHardJEE

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Q.50. Find Tension and spring force

This question includes visual content: A diagram shows an accelerating system moving upwards with acceleration 'a_0'. At the top, there is a spring inside a rectangular frame, attached to a pulley below. The pulley supports two masses, 'm_1' and 'm_2', hanging from a string passing over it. The tension 'T' acts upwards on both masses. The force 'F_s' acts upwards on the center of the pulley from the spring.

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Step 1

Hi Mohammad, let's solve this mechanics problem together.

Find Tension and Spring Force

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Step 2

The problem asks us to find the tension in the string, T, and the force in the spring, F sub S, for a system accelerating upwards with acceleration a sub zero.

a₀m₁m₂TTFs
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Step 3

To solve this, we can analyze the motion from the accelerating frame of reference of the pulley.

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Step 4

In this non-inertial frame, each mass experiences a downward pseudo force equal to its mass times the upward acceleration, a sub zero.

Frame of Reference

Since the system is accelerating upwards at $a_0$, the effective gravity acting on the masses is modified.

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Step 5

This means we can work with an effective gravity, which is g plus a sub zero.

$$g_{\text{eff}} = g + a_0$$
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Step 6

Now, we can set up the equations of motion in this pulley frame, where the two masses act as a standard Atwood machine under effective gravity.

Equations of Motion in Pulley Frame

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Step 7

Assuming mass m sub one is heavier and moves downward with relative acceleration a sub r, the equation for m sub one is m sub one times effective gravity minus tension T equals m sub one times a sub r.

$$m_1(g + a_0) - T = m_1 a_r$$
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Step 8

For mass m sub two, which moves upward with acceleration a sub r, the equation is tension T minus m sub two times effective gravity equals m sub two times a sub r.

$$T - m_2(g + a_0) = m_2 a_r$$
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Step 9

Let's isolate the relative acceleration in both equations by dividing by the respective masses.

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Step 10

Since both expressions equal a sub r, we can set them equal to each other.

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About This Question

Subject
Physics
Topic
Newton's Laws of Motion
Difficulty
Hard
Exam
JEE
Question Type
Open Ended

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