Simplify Radical Expression

MathematicsRadicalsMediumSTEM

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6. $5\sqrt[4]{6x} \cdot -3\sqrt[4]{27x^3}$

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Step by Step Written Solution

1
Step 1

In this problem, we are asked to simplify the product of two radical expressions. Let's write them down first.

Problem: Simplify

$$5\sqrt[4]{6x} \cdot -3\sqrt[4]{27x^3}$$
2
Step 2

Because we are multiplying these two terms together, we can use the associative and commutative properties of multiplication to group the constants and the radicals.

3
Step 3

First, let's multiply the coefficients five and negative three to get negative fifteen.

4
Step 4

Next, we apply the product property of radicals, which states that the product of two fourth roots is equal to the fourth root of their products.

Product Rule: $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$

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Step 5

Now we can combine the terms inside the radical. Six times twenty seven gives us one hundred and sixty two, and x times x cubed is x to the fourth power.

Note: $x^1 \cdot x^3 = x^{1+3} = x^4$

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Step 6

To simplify further, we should check if one hundred and sixty two has any factors that are perfect fourth powers.

Simplifying the Radical

$$-15\sqrt[4]{162 \cdot x^4}$$

Factor 162: $162 = 81 \cdot 2$

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About This Question

Subject
Mathematics
Topic
Radicals
Difficulty
Medium
Exam
STEM
Question Type
Open Ended

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