Organic Chemistry Reaction Tree and Nomenclature
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(c) Use the flow chart to answer the questions that follow.
[Flow Chart Description:
- Center: $CH_3CH_2OH_{(l)}$
- Step I: reacts with $Na_{(s)}$ to produced $H_2$ and $C$.
- Step II: produces $H_2O_{(l)}$ and $CH_3COOCH_2CH_{3(aq)}$.
- Step III: produces $C_2H_{4(g)}$.
- Step IV: $C_2H_{4(g)}$ converted to $C_2H_{6(g)}$.
- Step V: $C_2H_{4(g)}$ reacts with $HCl_{(g)}$ to form B.
- Step VI: $CH_3CH_2OH_{(l)}$ reacts with Air to form Products.]
(i) Name
I. The type of reaction that occurs in the step II (1 mark)
II. Substance B (1 mark)
(ii) Give the formula of substance C (1 mark)
(iii) Give the reagent and the condition necessary for the reaction in step (IV) (3 marks)
2.
(a) Give the name of the following compounds:
(i)
$$\begin{matrix} & CH_3 \\ & | \\ CH_3 - & C & - CH_3 \\ & | \\ & CH_3 \end{matrix}$$ (1 mark)
(ii) $CH_3 C \equiv C CH_2CH_3$ (1 mark)
(b) Describe a chemical test that can be carried out in order to distinguish between
$$\begin{matrix} & CH_3 \\ & | \\ CH_3 - & C & - CH_3 \\ & | \\ & CH_3 \end{matrix}$$ and $CH_3 C \equiv C CH_2CH_3$ (2 marks)
This question includes visual content: The image contains two main sections. Section 1 is a reaction flow chart centered on ethanol ($CH_3CH_2OH_{(l)}$). Step I adds $Na_{(s)}$ to produce $H_2$ and $C$. Step II produces $H_2O$ and $CH_3COOCH_2CH_{3(aq)}$. Step III leads to $C_2H_{4(g)}$, which in Step V reacts with $HCl_{(g)}$ to form B, and in Step IV reacts to form $C_2H_{6(g)}$. Step VI involves reaction with Air to form 'Products'. Section 2 contains: (a)(i) a structural formula of neopentane (2,2-dimethylpropane) with a central Carbon bonded to four Methyl groups; (a)(ii) a linear formula $CH_3C \equiv CCH_2CH_3$; (b) asks for a test to distinguish the compounds in (a).
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Step by Step Written Solution
Let's work through this series of organic chemistry questions, starting with the flow chart centered around ethanol.
Organic Chemistry: Ethanol Reactions & Nomenclature
In part one, we first look at step Roman numeral two. We see ethanol reacting to form water and ethyl ethanoate. This is a reaction between an alcohol and a carboxylic acid, known as esterification.
Part 1 (i) - Step II Reaction Type
So, the answer for Step Roman numeral two is esterification.
Now, let's identify substance B in step five. Ethanol dehydrates in step three to form ethene, C two H four. In step five, ethene reacts with hydrogen chloride gas in an addition reaction.
Part 1 (i) - Substance B
The product is chloroethane. So substance B is chloroethane.
Next, let's look at step one to find substance C. Sodium metal reacts with ethanol to displace hydrogen gas.
Part 1 (ii) - Substance C
The salt produced is sodium ethoxide. Its formula is C two H five O N a.
For part three, we need the reagent and conditions for step four, which turns ethene into ethane.
Part 1 (iii) - Step IV Reagents
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