Calculate Resistivity of a Wire
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Q.60 A wire with length $2 \text{ m}$ and cross-sectional area $3 \text{ mm}^2$ carries a current of $5 \text{ A}$ when connected to a $15 \text{ V}$ battery. What is the resistivity of the wire?
A. $2 \times 10^{-6} \text{ } \Omega\text{m}$
B. $4.5 \times 10^{-6} \text{ } \Omega\text{m}$
C. $4.5 \times 10^{-7} \text{ } \Omega\text{m}$
D. $3.2 \times 10^{-6} \text{ } \Omega\text{m}$
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Hi Hoorain, let's solve this physics problem together.
Analyzing the Circuit
First, let's list our given values. We have the length of the wire is two meters, the cross-sectional area is three millimeters squared, the current is five amperes, and the voltage is fifteen volts.
Since we need to find the resistivity, we first need to determine the resistance of the wire using Ohm's Law.
Step 1: Resistance
Plugging in our values, fifteen divided by five gives us a resistance of three ohms.
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