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Hi Ozodbek, let's solve this chemistry problem about atmospheric corrosion together.

The problem states that eleven point two grams of iron increased in mass by seven point five grams due to corrosion. This increase in mass represents the oxygen and water that combined with the iron to form rust.

First, let's calculate the number of moles of iron we started with. The molar mass of iron is fifty-six grams per mole.

Now, rust is generally represented as iron three oxide with some number of water molecules, often written as Fe-two-O-three times n molecules of water.

From the formula, we see there are two iron atoms for every formula unit. Since we have zero point two moles of iron, we will have zero point one moles of the rust complex.

The mass of this rust is the initial mass of iron plus the mass increase, which equals eighteen point seven grams.