Stress Increase Under Circular Loaded Area
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Lect. 8 - 5:
A flexible circular area is subjected to a uniformly distributed load of $150\text{ kN/m}^2$ shown in figure below. The diameter of the loaded area is $2\text{ m}$. Determine the stress increase $\Delta\sigma$ in a soil mass at a point located $3\text{ m}$ below the loaded area at $r = 0.0, 0.4\text{ m}, 0.8\text{ m},$ and $1\text{ m}.$
Use Boussinesq's solution
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Hi arjan, let's solve this geotechnics problem where we calculate the stress increase beneath a flexible circular loaded area using Boussinesq's theory.
Determining Stress Increase under a Circular Area
Let's list the given parameters first. We have a uniformly distributed load, lowercase q, of one hundred fifty kilonewtons per square meter.
The diameter is two meters, which means the radius R of the circular area is one meter. We are looking for the stress increase delta sigma at a depth z of three meters.
According to Boussinesq's solution for a circular area, the vertical stress increase depends on the ratios of radius over depth and radial distance over depth. We define two non-dimensional parameters, capital A and capital B.
Boussinesq Formula
For points not at the center, we use influence charts or updated formulas involving ratios. Here, r is the horizontal distance from the center. Let's calculate the common ratio r over z for each case.
We also need the ratio R over z, which is constant for all points in this problem.
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