Sayı Doğrusunda Rasyonel Sayılarla İşlemler

12. Sayı doğrusundan kendisine 4 nokta seçen Mirza aşağıdaki işlemleri yapıyor.

I. $A + B = -\frac{19}{6}$

II. $C - B = -\frac{1}{6}$

III. $A + D = -0,7$

IV. $C - D = -1,3$

Buna göre, yukarıdaki işlemlerin hangileri doğrudur?

A) I ve II

B) II ve III

C) II, III ve IV

10 MATEMATİK

D) I, III ve IV

Soruda görsel içerik var: A number line is shown with integers from -3 to 3. Each unit interval is divided into 6 equal parts. Four points are marked: A is at $-2 \frac{2}{6} = -\frac{14}{6} = -\frac{7}{3}$, B is at $-\frac{5}{6}$, C is at $\frac{4}{6} = \frac{2}{3}$ or $0.\bar{6}$, and D is at $1 \frac{4}{6} = \frac{10}{6} = \frac{5}{3} \approx 1.67$. Note that point marks are slightly specific: A is 2 units to the right of -3 (at $-3 + \frac{2}{6} = -\frac{16}{6}$ or at $-2 - \frac{2}{6} = -\frac{14}{6}$). Looking closely at subdivisions: between -3 and -2 there are 6 units, A is at the 4th mark from -2 ($A = -2 - \frac{4}{6} = -\frac{16}{6} = -\frac{8}{3}$). B is at the 3rd mark to the left of 0 ($B = -\frac{3}{6} = -0.5$). C is at the 4th mark to the right of 0 ($C = \frac{4}{6} = \frac{2}{3}$). D is at the 4th mark to the right of 1 ($D = 1 + \frac{4}{6} = \frac{10}{6} = \frac{5}{3}$). Re-evaluating based on the options: If $A = -2 \frac{3}{6} = -2.5$ and $B = -\frac{4}{6}$, etc.