Organic Reactions Scheme Analysis

1. (a) What is an unsaturated hydrocarbon compound (1mk)

(b) The scheme below shows a series of reactions starting with propanol. Study it and answer the questions that follow.

(i) Name the type of reaction in step I and II (2mks)

(ii) Write the equation for the reaction that takes place in Step III (1mks)

(i) Name the substance labelled A, C, D and E. (2mks)

(ii) Draw the structural formula of product C (1mk)

(iii) Name the process in step (IV) (1mk)

(iv) Name compound B and state the type of reaction involved in its formation. (2mks)

(v) If the relative molecular mass of B is 35,700 determine the value of n. (2mks)

This question includes visual content: A flowchart showing chemical reactions. Propanol reacts via Step I (H+/KMnO4) to propanoic acid ($CH_3CH_2COOH$), which then reacts with potassium to produce 'Solution A + Hydrogen gas' and with propanol/butanol to form an ester, or with sodium to form $CH_3CH_2COONa$. $CH_3CH_2COONa$ leads to $CH_3CH_3$ (ethane) in Step 3, which then forms 'Compound D + HCl'. Separately, propanol reacts via Step II to $CH_2=CHCH_3$ (propene), which reacts with HCl to form 'Compound E' and with $Cl_2$ (implied polymerization) to form 'Compound B'. Step IV shows the reaction of propanoic acid with butanol in the presence of conc. $H_2SO_4$ to produce 'Product C + H2O'.