Finding the time for a sinusoidal current

PhysicsAlternating CurrentMediumJEE

Published: August 9, 2026

Question

Q.50 For $I = 5 \sin(50\pi t)$, first time current reaches $2.5\text{ A}$ is:

A. $1/150\text{ s}$

B. $1/300\text{ s}$

C. $1/50\text{ s}$

D. $1/100\text{ s}$

Animated Video Solution

The first half plays free, the full solution is in the app.

Step 1

Hi Hoorain, let's solve this alternating current problem together.

Step 2

We are given the current equation as I equals five sine of fifty pi t. We need to find the first time this current reaches two point five amperes.

I = 5 \sin(50\pi t)

I = 2.5 \; \text{A}

Step 3

Let us substitute two point five for I into our equation.

2.5 = 5 \sin(50\pi t)

Step 4

Now, divide both sides by five to isolate the sine function. Two point five divided by five equals one half.

\sin(50\pi t) = 0.5

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