Electric Field Magnitude at a Square Corner
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Soru 3
Two point charges $q_1 = -7,1Q$ and $q_2 = 8,8Q$ are located at the corners of the square as shown in the figure below. Find the magnitude of the electric field vector at the top right corner of the square in terms of $\frac{kQ^2}{l^2}$. Express your answer using one decimal place.
Cevap:
Cevap
This question includes visual content: A square with side length l is shown. At the top-left corner, there is a red point charge labeled q1. At the bottom-right corner, there is a blue point charge labeled q2. The top-right corner is empty and serves as the observation point. Side lengths are marked with the letter 'l' on the top and right segments.
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Step by Step Written Solution
In this problem, we need to find the magnitude of the net electric field at the top right corner of a square created by two point charges, q1 and q2. Let's start by looking at the given values.
Electrostatics: Electric Field of Point Charges
The electric field at a point is given by the formula E equals k times q over r squared, where r is the distance from the charge to the point of interest.
Let's set up a coordinate system with the origin at the bottom-left corner. The top right corner is at coordinates l comma l.
Charge q1 is at the top left corner. Its distance to the top right corner is exactly l.
Since q1 is negative, the field vector E1 points towards the left, towards q1.
Charge q2 is at the bottom right corner. Its distance to the top right corner is also exactly l.
Since q2 is positive, the field vector E2 points upwards, away from q2.
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