Digital Logic Circuit Analysis with 7483 and 7486 Chips

Electrical EngineeringDigital Logic and Adder Subtractor CircuitsMediumSTEM

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Analyze the provided digital logic circuit. Given the logic states for inputs $A_0, A_1, A_2, A_3$, control signal $M$, and inputs $U_{11}, U_{12}, U_8, U_9$, predict or verify the operation of the 4-bit adder/subtractor circuit and the resulting output states shown by the indicators $X_1$ through $X_5$.

This question includes visual content: A digital circuit schematic showing two integrated circuits: U1 (7483N, a 4-bit full adder) and U2 (74LS86N, quad XOR gates). Inputs are labeled A0=0, A1=0, A2=0, A3=1. There is also a control input M=1. Pins for U1 include A1-A4, B1-B4, S1-S4, and C0/C4. The B inputs of U1 are connected to the outputs of the XOR gates (U2). One input of each XOR gate is connected to M, and the other inputs are linked to U11, U12, U8, U9 which have logic states 0, 0, 0, 1 respectively. The outputs S1-S4 of U1 are connected to lamps X1, X2, X3, X4, and the carry-out C4 is connected to lamp X5. Lamps X2, X3, X4, and X5 are shown in blue (lit/active), while X1 is white (inactive).

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Step by Step Written Solution

1
Step 1

In this problem, we need to analyze a digital circuit containing a 7483 4-bit adder and a 74LS86 XOR gate IC. Our goal is to determine the state of the output LEDs based on the given logic inputs.

Circuit Analysis: 4-bit Adder/Subtractor

2
Step 2

Let's start by identifying the main components. U1 is a seven four eighty-three 4-bit binary adder. U2 is a seven-four LS eighty-six, which contains XOR gates. There is also a mode control input labeled M.


Key Components:

- U1: 7483N 4-bit Full Adder

- U2: 74LS86N XOR Gates

- M: Mode Control (1 = Subtraction, 0 = Addition)

3
Step 3

Now, let's identify the input values for the A operand. Looking at the diagram, A3 is one, A2 is zero, A1 is zero, and A0 is zero. So, binary A is one zero zero zero, which is decimal eight.

$$A = (A_3 A_2 A_1 A_0)_2 = (1000)_2$$
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Step 4

Next, let's look at the second operand, which we'll call B. Notice that the inputs U8, U9, U11, and U12 are fed into XOR gates along with the mode control M. Let's record these raw values first.

$$Input\ B: U_{11}=0, U_{12}=0, U_8=0, U_9=1 \rightarrow (0001)_2$$
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Step 5

Wait, the schematic shows the XOR output going to the B pins of the adder. Mode control M is set to one. When M is one, the XOR gates invert the input values, effectively prepping for two's complement subtraction.

6
Step 6

Let's calculate the values actually entering the B ports of the adder. The adder's B inputs receive the XOR of the switch values and M. Since M is one, the inputs are inverted.

Adder Input Calculation

$$B_{adder} = B_{in} \oplus M$$

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About This Question

Subject
Electrical Engineering
Topic
Digital Logic and Adder Subtractor Circuits
Difficulty
Medium
Exam
STEM
Question Type
Open Ended

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