Circuit Analysis of a Lamp and Resistors
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Question 10. Functioning of a Lamp. A lamp $L$ $(4\text{V}; 2\text{W})$, a dry cell $G$ $(12\text{V})$ and two resistors of resistances $R_1$ and $R_2$ are connected in an electric circuit as shown in the given diagram. A- Switch $K$ is closed, the lamp functions normally, and the current sent by the dry cell $I_{\text{Cell}} = 2\text{A}$. 1. Determine the current that traverses $L$ when it functions normally. 2. Determine the current that traverses each one of the two resistors. 3. Find the voltages $U_{SH}$ and $U_{ST}$. 4. Calculate $R_1$ and $R_2$. 5. Determine the resistance of the equivalent resistor of $R_1$, $R_2$ and $L$. 6. Calculate, in J and kWh, the energy consumed by the circuit in 20 hours. B- The terminals $T$ and $S$ were joined accidentally by a connecting wire. 1. Does the lamp function normally in this case? Justify your answer. 2. What would happen to the lamp? 3. What safety element should be added to the circuit in order to protect the lamp from such accident? 4. Give the inscriptions of the safety element and show its connection in the circuit.
This question includes visual content: The image shows a circuit diagram composed of a DC voltage source, a lamp (symbolized by a circle with an X), and two rectangular blocks representing resistors labeled R1 and R2. The circuit includes junction points labeled T, S, H, M, P, and N. The lamp is in a parallel configuration with R2, and this parallel combination is in series with R1. The circuit contains a switch labeled K.
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In this problem, we analyze a circuit with a lamp, a battery, and resistors. We are given the lamp's rated power and voltage, and we know it functions normally when the switch is closed.
Circuit Analysis: Functioning of a Lamp
Let's list the known values. The lamp is rated at four volts and two watts. The dry cell provides twelve volts, and the total current from the cell is two amperes.
For part one, let's determine the current through the lamp. Since it functions normally, it uses its rated power and voltage.
1. Lamp Current ($I_L$)
Rearranging for current, we get P divided by U. Substituting two watts and four volts, we find the lamp current is zero point five amperes.
Next, let's find the current through the resistors. Note that the lamp L and resistor R two are in parallel, and this combination is in series with R one.
2. Resistor Currents
Because R one is in the main branch, its current is the total cell current, which is two amperes. Using the law of addition of currents at node S, we can find the current through R two.
Subtracting zero point five from two, we find that the current through R two is one point five amperes.
Part three asks for the voltages across the sections. The lamp is in parallel with R two, so their voltage is the lamp's rated voltage, four volts.
3. Voltages $U_{SH}$ and $U_{ST}$
According to the law of addition of voltages, the supply voltage equals the sum of the voltages in series. So twelve volts equals U plus four volts.
Subtracting four from twelve, we find that the voltage across R one is eight volts.
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