Chlorine Reaction Scheme Analysis

49. Study the reaction scheme below and answer the questions that follow: [Reaction Scheme showing Chlorine + Hydrogen -> Step 1 -> Substance M -> Water -> Step 2 -> Solution N; from N -> NaHCO3 -> Step 3 -> Solution P, Liquid Q, Gas R; from N -> Lead (IV) oxide -> Step 4 -> Gas U -> Water -> Step 5 -> Mixture of two acids S+T -> Sunlight -> Step 6 -> Solution V + Gas W; from Gas U -> FeCl2(aq) -> Step 7 -> FeCl3] (5mks) a) Identify the following substances labeled: i) Substance M, ii) Solution N, iii) Solution P, iv) Liquid Q, v) Gas R, vi) Gas U, vii) Acid S, viii) Acid T, ix) Solution V, x) Gas W (5mks) b) Explain the observation made in the following steps: i) Step 3, ii) Step 4, iii) Step 6, v) Step 7 (6mks) c) Write equations for reactions taking place at at the following steps: i) Step 1, ii) Step 3, iii) Step 5, iv) Step 5, v) Step 6, vi) Step 7 (1mk each) d.i) What is the type of reaction taking place at step 7. ii) Identify the property of gas U demonstrated in step 7. Give a reason (1mk) e) What is the industrial application for the reactions taking place at steps 1 and 2? (?) f) Identify the substance that is used in step 2 to dissolve gas M in water successful. Explain your answer. (1mk) h) The reaction in step 1 can be explosive, give reason for this and state how explosion is avoided (2mks)

This question includes visual content: The image contains a flowchart of chemical reactions. It starts with Chlorine and Hydrogen reacting at Step 1 to form Substance M. Substance M plus Water at Step 2 results in Solution N. Solution N reacts with NaHCO3 at Step 3 to form Solution P, Liquid Q, and Gas R. Solution N reacts with Lead (IV) oxide at Step 4, yielding Gas U. Gas U plus Water at Step 5 gives a mixture of two acids S and T. Acids S and T under sunlight at Step 6 yield Solution V and Gas W. Gas U plus FeCl2 (aq) at Step 7 results in FeCl3.