Characteristic of an Integral Domain

MathematicsAbstract AlgebraHard

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Question 3 Let $D$ be an integral domain. Prove that $char(D)$ is either zero or a prime number.

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Step by Step Written Solution

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Step 1

Hi Testere, let's look at this abstract algebra proof together. We're going to prove that the characteristic of an integral domain D must be either zero or a prime number.

Characteristic of an Integral Domain

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Step 2

First, let's recall what the characteristic and an integral domain are.


Definitions

- Integral Domain (D): A commutative ring with unity $1 \neq 0$ and no zero divisors.

- Characteristic (char D): The smallest positive integer $n$ such that $n \cdot 1 = 0$. If no such $n$ exists, the characteristic is $0$.

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Step 3

Suppose the characteristic of D is not zero. We want to show it must be a prime number. To do this, we'll use a proof by contradiction.

The Proof

Assume $\text{char}(D) = n$, where $n > 0$.

Goal: Show $n$ is prime.

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Step 4

Let's assume the opposite: that $n$ is a composite number.

$$n \text{ is composite} \implies n = ab$$
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Step 5

This means we can write n as the product of two smaller integers, a and b, where both are greater than one and less than n.

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Step 6

Since the characteristic of the domain is n, we know that n times the multiplicative identity, one, equals zero.

$$n \cdot 1 = 0$$
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Step 7

Now, we can substitute our product a times b in place of n.

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Step 8

By the properties of ring multiplication and the identity element, we can rewrite this product. Note that one squared is just one.

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Step 9

Let's look closely at this equation. We have a product of two elements from our domain equal to zero.

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About This Question

Subject
Mathematics
Topic
Abstract Algebra
Difficulty
Hard
Question Type
Proof

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