حساب القوة الدافعة الكهربائية

PhysicsElectric CircuitsMedium

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الشكل المقابل يمثل جزء من دائرة كهربية يمر بها تيار كهربى، فتكون قيمة $V_B$ هي ............. (تجريبي ٢٥)

(أ) $30 \text{V}$

(ب) $25 \text{V}$

(ج) $20 \text{V}$

(د) $15 \text{V}$

This question includes visual content: يحتوي الشكل على دائرة كهربائية تتكون من مصدر جهد $V_B$ (بمقاومة داخلية $r=0$) متصل على التوالي مع مقاومة $2 \Omega$، ومقاومة $20 \Omega$ في فرع عمودي، ومقاومة $3 \Omega$ في الفرع السفلي. يظهر اتجاه التيار $1 \text{A}$ يخرج من المصدر، وتيار $2 \text{A}$ يدخل إلى العقدة في الأعلى بالقرب من المقاومة $20 \Omega$. الأسهم تشير إلى اتجاهات التيارات في أجزاء الدائرة.

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Step by Step Written Solution

1
Step 1

Hi fares, let's solve this electrical circuit problem together. We need to find the value of the battery voltage, V B, based on the current and resistance values given in the diagram.

حساب القوة الدافعة الكهربائية $V_B$

2
Step 2

First, let's look at the junction at the top right. We have two amperes entering from the right and one ampere leaving to the left through the two ohm resistor.

2 A (In)1 A (Out)
3
Step 3

According to Kirchhoff's Current Law, the sum of currents entering a junction must equal the sum of currents leaving it. So, the current flowing down through the twenty ohm resistor must be two minus one, which is one ampere.

$$I_{20̦} = 2 - 1 = 1 ; \text{A}$$
4
Step 4

Now let's apply Kirchhoff's Voltage Law to the left-hand loop. We'll start from the battery and go clockwise.

قانون كيرشوف الثاني (قانون الجهود)

$$∑ V = 0$$

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About This Question

Subject
Physics
Topic
Electric Circuits
Difficulty
Medium
Question Type
Multiple Choice

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